solve the following linear equation
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Given,
x/2 + y = 0.8
→(x+2y)/2 = 0.8
→x+2y =1.6
→5(x+2y)= 1.6*5
→5x + 10y = 8.0.............(i)
And,
→7/(x +y/2) = 10
→14/(2x +y) = 10
→10(2x+y) = 14
→5(2x+y)= 7
→10x +5y =7
→2(10x +5y) =7*2
→20x + 10y = 14......................(ii)
Now,
Substracting equation (i) form (ii)
We get,
15 x = 6
x= 6/15
x= 2/5
PUTTING x= 2/5 in equation (ii)
(2/5)/2 +y= 0.8
y= 3/5
Refer to attachment
x/2 + y = 0.8
→(x+2y)/2 = 0.8
→x+2y =1.6
→5(x+2y)= 1.6*5
→5x + 10y = 8.0.............(i)
And,
→7/(x +y/2) = 10
→14/(2x +y) = 10
→10(2x+y) = 14
→5(2x+y)= 7
→10x +5y =7
→2(10x +5y) =7*2
→20x + 10y = 14......................(ii)
Now,
Substracting equation (i) form (ii)
We get,
15 x = 6
x= 6/15
x= 2/5
PUTTING x= 2/5 in equation (ii)
(2/5)/2 +y= 0.8
y= 3/5
Refer to attachment
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