Question

Solve the following linear equation :- 4x - 3y = 8 and x - 2y = -3​

Answer 1

Step-by-step explanation:

4x - 3y = 8

x - 2y = -3

x = -3 + 2y

x = 2y -3

substituting x= 2y-3 in 4x - 3y = 8

4(2y-3) - 3y = 8

8y - 12 - 3y = 8

5y -12 = 8

5y = 8+12

5y = 20

y=20/5

y=4

x=2y - 3

x= 2(4)-3

x=8-3

x=5

Answer 2

Answer:

4x-3y=8

$x = \frac{8 + 3y}{4}$

put value of x in equation 2

x-2y=-3

$\frac{8 + 3y}{4} - 2y = - 3$

$\frac{8 + 3y - 8y}{4} = - 3$

8-5y=-12

-5y=-20

y=4

put value of y in equation 1

$x = \frac{8 + 3y}{4} = \frac{20}{4} = 5$

hence,x=5 and y=4