Question

solve the following linear equation 5/x-1+1/y-2=2, 6/x-1-3/y-2=1​

Answer 1

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Step-by-step explanation:

According to question

$\frac{5}{x - 1} + \frac{1}{y - 2} = 2 - - - - (1)$

$\frac{6}{x - 1} - \frac{3}{y - 2} = 1 - - - - (2)$

on solving the equation (1)

$5(y - 2) + 1(x - 1) = 2(x - 1)(y - 2)$

$5y - 10 + x - 1 = 2(xy - 2x - y + 2) \\ 5y - 11 + x = 2xy - 4x - 2y + 4 \\ 7y + 5x + 2xy = 15 - - - - - (3)$

now solving equation 2

$6(y - 2) - 3(x - 1) = (x - 1)(y - 2) \\ 6y - 12 - 3x + 3 = xy - 2x - y + 2 \\ 7y - x - xy = 11 - - - - - (4)$

now by elimination method solve equation (3) and (4) we get the value of

x and y.

Answer 2

Answer:

on solving the equation (1)

now solving equation 2

now by elimination method solve equation (3) and (4) we get the value of

x and y.

Step-by-step explanation: