Question

solve the following linear equation 5y-1=3y+4 and
7(x+4)=2x-7​

Answer 1

Given:-

• $5y-1=3y+4..(1)$
• $7(x+4)=2x-7..(2)$

To Find:-

• The values of x and y.

Solution:-

First Solving the equation (1):

$5y-1=3y+45y−1=3y+4$

For Solving ,

we will Transpose the y Variable on left hand side and Numerical Value on Right hand side

$= > 5y - 3y = 4 + 1$

$= > 2y = 5$

$= > y = \frac{5}{2}$

Now Solving (2) equation:

$7(x+4)=2x-77(x+4)=2x−7$

Now we will Open the bracket by Multiplying 7 with (x+4)

$= > 7x + 28 = 2x - 7$

For Solving ,

we will Transpose the x Variable on left hand side and Numerical Value on Right hand side

$= > 7x - 2x = - 7 - 28$

$= > 5x = - 35$

$= > x = \frac{ - 35}{5}$

$= > x = - 7$

Therefore,

• x= -7
• y= 5/2