Question

solve the following linear equation 5y-1=3y+4 and
7(x+4)=2x-7​

Answer 1

Answer:

$\sf\red{Solution:-}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\sf{5y - 1 = 3y + 4}$

$\sf{5y - 3y =4 + 1}$

$\sf{2y =5}$

$\sf \red{y = \frac{2}{5} }$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\sf{7(x +4) = 2x - 7}$

$\sf{7x +28 = 2x - 7}$

$\sf{7x - 2x = - 7 - 28}$

$\sf{5x = - 35}$

$\sf{x = - \frac{ \cancel35}{ \cancel5} }$

$\sf \red{x = - 7 }$

Answer 2

Step-by-step explanation:

$5y1 = 3y + 4$

$5y - 3y = 4 + 1$

$2y = 5$

$y = \frac{2}{5}$

$7(x + 4) = 2x - 7$

$7x + 28 = 2x - 7$

$7x-2x = -7 - 28$

$5x = -35$

$x = \frac{35}{7}$

$x = 7$