solve the following linear equation by eliminating
3/x+y+2/x-y =3; 2/x+y + 3/x-y= 11/3
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2
Answer:
X = 2 , Y = 1
Step-by-step explanation:
Multiply first equation by 2 and second equation by 3 and subtract.
(6/x+y + 4/x-y) - (6/x+y + 9/x-y) = 6 - 11
- 5/x-y = - 5
x-y = 1 ----------------> Equation 1.
Multiply first equation by 3 and second equation by 2 and subtract.
(9/x+y + 6/x-y) - (4/x+y + 6/x-y) = 9 - 22/3
5/x+y = 5/3
x+ y = 3 ============> equation 2
Add equation 1 and equation 2
x -y = 1
x + y = 3
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2x = 4 => x = 2,
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substitute value of x in equation 1 =>
2 - y = 1 ===> y = 1.
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