solve the following linear equation by subsitution method
4x-3y=8
x-2y=-3
Answers
Answered by
1
Answer:
4x-3y=8
x-2y=-3 or x=2y-3
placing the value of x in eq 1
4(2y-3)-3y=8
8y-3y-12=8
5y=20
y=4
thus x=2*4-3
=8-3
=5
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Answered by
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Question
solve the following linear equation by substitution method
4x-3y=8
x-2y=-3
Solution
Given:-
- 4x - 3y = 8 -----------(1)
- x - 2y = -3 --------------(2)
Find:-
- Value of x & y
Explanation
Substitution method
By , equation (1)
==> 4x = 8 + 3y
==> x = (8 + 3y)/4 -------------(3)
Substitute value of x in equ(2),
==> (8+3y)/4 - 2y = -3
==> 8 + 3y - 8y = -12
==> 8 - 5y = -12
==> 5y = 8 + 12
==> y = 20/5
==>y = 4
keep value of y in equ(3),
==> x = [8+3*4 ]/4
==> x = [8 + 12]/4
==> x = 20/4
==>x = 5
Thus
- Value of x = 5
- Value of y = 4
Answer verification
Keep value of x & y in equ(2)
==>5 - 2 * 4 = -3
==> 5 - 8 = -3
==> -3 = -3
L.H.S. = R.H.S.
That's proved.
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