solve the following linear equation by substitution method 3 X + 4 Y is equals to 10 and X + 2 Y is equal to 2
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3x+4y=10
{x+2y=2}×3
3x+6y=6
3x+4y=10
3x+6y=6
_ _ _
-2y=-4
y=-4/-2
y=2
{x+2y=2}×3
3x+6y=6
3x+4y=10
3x+6y=6
_ _ _
-2y=-4
y=-4/-2
y=2
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