Math, asked by hanshikanayak18, 2 months ago

solve the following linear equation in one variable
i )  \: 5y - y + 1  \div 3 = 6y  + 1 \div 5

Answers

Answered by valarmathirp71
1

Answer:

My best answer is, y = -1

I hope it will help you.

Answered by poojadancer007delhi
1

Answer:

5y -y +1÷ 3. =. 6y + 1 ÷ 5

4y + 1 ÷ 3 = 6y + 1 ÷ 5

5(4y + 1 ) = 3( 6y +1)

20y + 5 = 18y + 3

20y - 18y = 3-5

2y = -2

y = -2/2

y = -1

Similar questions