Question

Solve the following linear equation:
(x+2)/3-(x+1)/5=(x-3)/4-1

Answer 1

Step-by-step explanation:

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Answer 2

Solution -

$\sf{ \dfrac{(x + 2)}{3} - \dfrac{(x + 1)}{5} \: = \dfrac{(x - 3)}{4} - 1} \\ \\ \sf{\dfrac{(x + 2)}{3} - \dfrac{(x + 1)}{5} -\dfrac{(x - 3)}{4} = - 1 } \\ \\ \sf{taking \: lcm \: } \: \\ \\ \sf{ \implies{ \dfrac{20(x + 2) - 12(x + 1) - 15(x - 3)}{60} = - 1}} \\ \\ \sf{ \implies{ \dfrac{2x + 20 - 12 x- 12 - 15x + 45}{60} = - 1}} \\ \\ \sf{ \implies{ \dfrac{- 25x + 53}{60} = - 1}} \\ \\ \sf{ \implies{ - 25x + 53 = - 60}} \\ \\ \sf{ \implies{ - 25x = - 113}} \: \: \\ \\ \sf{ \implies{x = \dfrac{113}{25}}} \: ......(a)$