Question

Solve the following linear equations:
3y-1/5 - 1+y/2 = 3 - y- 1/4

Answer 1

Answer:

y = 2/35

Step-by-step explanation:

3y-1/5 - 1+y/2 = 3-y-1/4

=> 15y-1/5 - 2+y/2 = 3-y-4

=> 2(15y-1) - 5(2+y) / 10 = 3-y-4

=> 30y-2-10-5y / 10 = 3-y-4

=> 25y-12 = ( 3-y-4) 10

=> 25y-12 = 30-10y-40

=> 25y-12 = -10-10y

=> 25y+10y = -10+12

=> 35y = 2

=> y = 2/35

Answer 2

$\big\langle\Big\langle\bigg\langle\Bigg\langle\LARGE\underbrace{\underline{\sf{Understanding\;the\;Question\;:-}}}\big\rangle\Big\rangle\bigg\rangle\Bigg\rangle$

A Linear Equation in one variable is defined as ax + b = 0 or ax = c, where a, b and c are real numbers. Also, a ≠ 0 and x is an unknown variable. The solution of the equation ax + b = 0 is x = - b/a. We can also say that - b/a is the root of the linear equation ax + b = 0.

Let's do it !!

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★ Formula Used :-

Here the Concept of Linear Equations has been used . We see that we are given a equation . If we solve the given equation, then we will get value which is not correct according to question . So correct question is mentioned below . After simplifying the question, we will get a Quadratic equation and we need to solve that equation to get answer .

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★ Solution :-

$\mathbb{GIVEN} \;,$

$=\testsc{3y}-\frac{1}{5}-\frac{1+y}{2} = 3 - y- \frac{1}{4}$

$\textsc {Subtracting the numbers:-}$

$={3y}-\frac{6}{5}-\frac{1+y}{2} = 3 - y- \frac{1}{4}$

$\textsc{Again Subtracting the numbers:-}$

$=\testsc{3y}-\frac{1}{5}-\frac{1+y}{2} = \frac{11}{4} - y$

$\textsc{Rearranging the terms:-}$

$y=\frac{79}{90}$

Hence, Verified,

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