Math, asked by Siddhi24345, 4 months ago

Solve the following linear equations and check your answer.
a)6x+8 =3(x-1)+11
b) 5x-3=7(2x+3)

Answers

Answered by vipashyana1
1

Answer:

a)6x+8 =3(x-1)+11 \\ </p><p>6x+8=3x-3+11 \\ </p><p>6x-3x=11-3-8 \\ </p><p>3x=0 \\ </p><p>x= \frac{0}{3}  \\ </p><p>x=0 \\ </p><p>6x+8 =3(x-1)+11 \\ </p><p>6(0)+8=3(0-1)+11 \\ </p><p>0+8=(-3)+11 \\ </p><p>8=8 \\ </p><p>LHS=RHS \\ </p><p>Hence  \: verified  \\  \\ </p><p>b)5x-3=7(2x+3) \\ </p><p>5x-3=14x+21 \\ </p><p>5x-14x=21+3 \\ </p><p>(-9x)=24 \\ </p><p>x=  \frac{24}{( - 9)} \\ </p><p>x=\frac{( - 8)}{3}  \\ </p><p>5x-3=7(2x+3) \\ </p><p>5( \frac{( - 8)}{3} )-3=7(2×\frac{( - 8)}{3} +3) \\ </p><p> \frac{( - 40)}{3} -3=7( \frac{( - 16)}{3} +3) \\ </p><p>\frac{( - 40) - 9}{3} =7( \frac{( - 16) + 9}{3} ) \\ </p><p>\frac{( - 49)}{3} =7× \frac{( - 7)}{3} \\ \frac{( - 49)}{3} =  \frac{( - 49)}{3}  \\ </p><p>LHS=RHS \\ </p><p>Hence \:  verified  \\

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