Solve the following linear equations by the substitution method
0.2x +0.3y=1.3
0.4x+0.5y=2.3
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0.2x+0.3y = 1.3
eq (i) ×10
2x+3y=13
0.4x+0.5y=2.3
eq(ii) ×10
4x+5y=23
from eq (i)
x =13-3y/2
putting value of x in eq (ii)
4(13-3y/2)+5y=23
26-6y+5y=23
26-y=23
y= 3
putting value of y in eq (i)
2x+3(3)=13
2x=13-9
x=4/2
x=2
eq (i) ×10
2x+3y=13
0.4x+0.5y=2.3
eq(ii) ×10
4x+5y=23
from eq (i)
x =13-3y/2
putting value of x in eq (ii)
4(13-3y/2)+5y=23
26-6y+5y=23
26-y=23
y= 3
putting value of y in eq (i)
2x+3(3)=13
2x=13-9
x=4/2
x=2
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