Question

Solve the following linear equations.
Plz answer this question with a pic and don't send useless answers ​

Answer 1

the answer for this question : t=2

Answer 2

Step-by-step explanation:

$\frac{3t-2}{4}$-$\frac{2t+3}{3}$=$\frac{2}{3}$-t

so now lets find $\frac{3t-2}{4}$-$\frac{2t+3}{3}$

Lcm=12

$\frac{3t-2}{4}$=$\frac{9t-6}{12}$

\frac{2t+3}{3}=$\frac{8t+12}{12}$

so, $\frac{9t-8-8t+12}{12}$

(rearrange)

$\frac{9t-8t-8+12}{12}$

=$\frac{t+4}{12}$

=$\frac{t}{3}$

so,$\frac{t}{3} =\frac{2}{3} - t$

=$t+\frac{t}{3} =\frac{2}{3}$

or,$\frac{t}{1} +\frac{t}{3} =\frac{2}{3}$

LCM=3

$\frac{t}{1} = \frac{3t}{3}$

=$\frac{3t}{3} +\frac{t}{3}$

=$\frac{4t}{3} =\frac{2}{3}$

to find t

$4t=\frac{2}{3}* \frac{3}{1}$

=$4t=2$

=t=2/4=0.5

happy to help  :)

mark me as brainliest