Math, asked by kethan22, 2 months ago

Solve the following linear equations.x/3+y/2 and 3x/4-y/4​

Answers

Answered by surekhabehera09
0

Answer:

By this photo you can easily get the answer

Attachments:
Answered by ishu200598
0

Answer:

X=-9

Y=6

Step-by-step explanation:

(x/3 + y/2 = 0)×3/4 (1)

3x/12 + 3y/12 = 0 (2)

(3x/4 - y/4 = 0 )×1/3

3x/12 - y/12 = 0 (3)

Subtracting equation 2 and equation 3 , we get

3x/12 + 3y/12 = 0

3x/12 - y/12 = 0

- +

3y/12 - y/12 = 0

3y-y = 0

12

2y/12 = 0

y/6 = 0

y = 6

putting the value of y in equation 1

x/3 + y/2 = 0

x/3 + 6/2 = 0

x/3 + 3 = 0

x/3 = -3

x = -3×3

x = -9

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