Solve the following linear equations.x/3+y/2 and 3x/4-y/4
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Answer:
X=-9
Y=6
Step-by-step explanation:
(x/3 + y/2 = 0)×3/4 — (1)
3x/12 + 3y/12 = 0 —— (2)
(3x/4 - y/4 = 0 )×1/3
3x/12 - y/12 = 0 ——(3)
Subtracting equation 2 and equation 3 , we get
3x/12 + 3y/12 = 0
3x/12 - y/12 = 0
- +
3y/12 - y/12 = 0
3y-y = 0
12
2y/12 = 0
y/6 = 0
y = 6
putting the value of y in equation 1
x/3 + y/2 = 0
x/3 + 6/2 = 0
x/3 + 3 = 0
x/3 = -3
x = -3×3
x = -9
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