solve the following linear inequaltion
-x/3<= x/2-4/3<1/6
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6x−5y=−1−−−eqn(2)
Multiplying equation 1 with 3 we get,
6x−45y=15−−−eqn(3)
Substracting equaton 1 from 3 we get,
−40y=16
y=
5
−2
=−0.4
Substituting y in eqn(2) we get,
6x+2=−1
x=
2
−1
=−0.5
So x<y
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