Math, asked by ayushdesai287, 5 months ago

solve the following linear inequaltion
-x/3<= x/2-4/3<1/6​

Answers

Answered by SIMnaN35
0

6x−5y=−1−−−eqn(2)

Multiplying equation 1 with 3 we get,

6x−45y=15−−−eqn(3)

Substracting equaton 1 from 3 we get,

−40y=16

y=

5

−2

=−0.4

Substituting y in eqn(2) we get,

6x+2=−1

x=

2

−1

=−0.5

So x<y

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