Question

solve the following linear pair of linear equations using substitution method a) 2x+3y=8. 4x+6y=7​

Answer 1

Question

a) 2x+3y=8. 4x+6y=7

Step-by-step explanation:

Step 1 : Multiply Equation (1) by 2 and Equation (2) by 1 to make the coefficients of x equal. Then we get the equations as : 4x + 6y = 16 ______(3) 4x + 6y = 7 ________(4)

Step 2 : Subtracting Equation (4) from Equation (3), (4x – 4x) + (6y – 6y) = 16 – 7 i.e., 0 = 9, which is a false statement. Therefore, the pair of equations has no solution.

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Answer 2

Answer:

• There are no solutions in this equation.

Step-by-step explanation:

Equations are:

1. 2x + 3y = 8
2. 4x + 6y = 7

To Find:

• The value of x and y using substitution method.

Finding the value of x and y:

In equation (1).

⟿ 2x + 3y = 8

⟿ 2x = 8 - 3y

In equation (2).

⟿ 4x + 6y = 7

⟿ 2(2x) + 6y = 7

Substituting the value of 2x.

⟿ 2(8 - 3y) + 6y = 7

⟿ 16 - 6y + 6y = 7

Cancelling 6y.

⟿ 16 = 7

But, It can't be true.

Hence,

• There are no solutions in this equation.