Question

solve the following logarithm ​

Answer 1

6+log3/2(1/3√2 √4-1/3√2-------)

√a√a√a√a√a√a√a√a√a--------=a

6+log3/2(1/3√2*√11/3√2----)

6+log3/2(1/3√2*11/3√2)

6+log3/2(11/18)

6+log3(11/18)-log2(11/18)

6+log33/18-log22/18

6+log11/6-log11/9

6+log11/6/11/9

6+log9/6

6+log3/2

6log 3/2+log 3/2

3/2

6log (3/2)^2

3/2

12log 3/2

3/2

12