Question

Solve the following LPP using Graphical method. Maximize z=6x₁ +8x₂ Subject to 5x +10x, ≤60 4x, +4x, ≤ 40 where .x1,x2 ≥0.
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Answer 1

To Maximize: Z=6x+4y

Constraints: x≤2

x+y≤3

−2x+y≤1

x≥0,y≥0

Plotting the constraints on the graph, we get the following points.

Points Z=6x+4y

O(0,0) 0 ← Minimum

A(0,1) 4

B(

3

2

,

3

7

)

3

40

C(2,1) 16 ← Maximum

D(2,0) 12

Hence, at C≡(2,1), Maximum value of Z=6x+4y=16.

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Answer 2

Answer:

Kiran Choudhary gave correct answer

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