Question

solve the following: m²n+mn²-3m²n² and -2mn²+3m²n-4m²n²-mn​

Answer 1

Answer:

4m²n-mn²+m²n²-mn

Step-by-step explanation:

m²n+mn²-3m²n²

+3m²n+mn²+m²n²-mn

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4m²n-mn²+m²n²-mn

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Answer 2

Given,

$m^{2}n+mn^{2}-3m^{2}n^{2}$ ______(1)

$-2mn^{2}+3m^{2}n-4m^{2} n^{2}-mn$_____(2)

Add the equation (1)and (2)

$=$ $m^{2}n+mn^{2}-3m^{2}n^{2}$$+$$($$-2mn^{2}+3m^{2}n-4m^{2} n^{2}-mn$$)$

$=m^{2}n+mn^{2}-3m^{2}n^{2}-2mn^{2}+3m^{2}n-4m^{2}n^{2}-mn$

$= 4m^{2}n-mn^{2} -7m^{2}n^{2}-mn$

$=m^{2}(4n-7n^{2}) -mn(n+1 )$

Therefore, the correct answer is $m^{2}(4n-7n^{2}) -mn(n+1 )$.