Question

Solve the following numerical


A body of mass 50 gram lies on a surface of dimensions 0.1 metre × 0.02 millimetre find the pressure exerted by the body

Answer 1

$m = 50g \: (c.g.s) \: = 50 \times {10}^{ - 3} kg \\ \\ = \geqslant l \: = 0.1m \: (s.i) \\ \\ = \geqslant b \: = 0.02mm \: (no \: system) \\ \\ = 0.02 \times 10 {}^{ - 3} \\ \\ = \geqslant p = \frac{f}{a} = \frac{mg}{l \times b} \\ \\ = \geqslant \frac{50 \times 10 {}^{ - 3} \times 9.8}{0.1 \times 0.02 \times 10 {}^{ - 3} } \\ \\ = \geqslant 50 \times 98 \times 50 \\ \\ = \geqslant 2500 \times 98 \\ \\ = \geqslant 245000 \: pascal$

Answer 2

hey mate ur answer is

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hope it's help