Question

solve the following one plessssssssssseeeeeeeee​

Answer 1

L.H.S = [(Sinθ +cos θ)² + (Sinθ -cos θ)²] /

Sin²θ-Cos²θ

=[ 2 Sin²θ + 2 Cos²θ ] / 1 -Cos²θ - Cos²θ

{ since, Sin²θ + Cos²θ =1

= [ 2 ( Sin²θ + Cos²θ) ] / 1 -2Cos²θ

= [ 2 × 1 ] / 1- 2Cos²θ

= 2 / [ (Sec²θ - 2 )÷ Sec²θ]

{ Since, Sec²θ -tan²θ = 1}

= 2 Sec²θ / (tan²θ -1)

= R.H.S

HENCE, L.H.S = R.H.S

Hope, it helps you!

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