solve the following pair by elimination method 7x- 2y= 5xy, 8 x+7y=15xy
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multiplying first equation by 3 we get
21x-6y = 15xy
the second equation is 8x+7y = 15xy
since both equal to 15xy so we can equate it
21x-6y = 8x +7y
21x-8x = 7y+8y
13x = 13y
x=y
now substituting this in any of the given equation we get
7x-2x = 5x*x
5x = 5x^2
5x^2 -5x = 0
x(x-1) = 0
x = 0,1. so
y = 0,1
hence x = y = 0,1
21x-6y = 15xy
the second equation is 8x+7y = 15xy
since both equal to 15xy so we can equate it
21x-6y = 8x +7y
21x-8x = 7y+8y
13x = 13y
x=y
now substituting this in any of the given equation we get
7x-2x = 5x*x
5x = 5x^2
5x^2 -5x = 0
x(x-1) = 0
x = 0,1. so
y = 0,1
hence x = y = 0,1
Anonymous:
yhanks
it's OK
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