solve the following pair by substitution and cross MULTIPLICATION...
I)8x+5y=9,3x+2y=7
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8x +5y =9
Subtract 8x both sides we get
5y = 9 – 8x
Divide by 5
Y = (9 – 8 x)/5 …(3)
Plug this value of y in equation second we get
3x +2y =4
3x + 2(9 – 8 x)/5) = 4
Multiply by 5 we get
15 x + 18 - 16 x = 20
-x = 2
X = - 2
Plug this value back in equation (3) we get
Y = (9- 8(-2))/5
Y = 25/5
Y = 5
Answer is x = -2 and y = 5
Cross multiplication method
8x +5y =9 …(1)
Subtract 9 both side we get
8x +5y – 9 = 0
3x +2y =4 …(2)
Subtract 4 both side we get
3x + 2y – 4 = 0
Compare with
we get
a1 = 8 , b1 = 5 , and c1 = -9
a2 = 3 , b2 = 2 and c2 = -4
Use the formula of cross multiplication
We get
x = -2 and y = 5
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