solve the following pair in substitution method 0.2x+0.3y=1.3,0.4x+0.5y=2.3
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0.2x+0.3y=1.3×10
0.4x+0.5y=2.3×10
2x+3y=13 (eq.1)
4x+5y=23 (eq.2)
take eq.1
x=13-3y÷2 (eq.3)
put x in eq. 2
4(13-3y÷2)+5y=23
2(13-3y)+5y= 23
26-6y+5y=23
-y=23-26
y=3
put y in (eq.3)
13-3×3÷2= x
x=13-9÷2
x=4÷2
x=2
0.4x+0.5y=2.3×10
2x+3y=13 (eq.1)
4x+5y=23 (eq.2)
take eq.1
x=13-3y÷2 (eq.3)
put x in eq. 2
4(13-3y÷2)+5y=23
2(13-3y)+5y= 23
26-6y+5y=23
-y=23-26
y=3
put y in (eq.3)
13-3×3÷2= x
x=13-9÷2
x=4÷2
x=2
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