solve the following pair of equation 3x - 4y = 1 and x-2y+1=0
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Answered by
2
3x - 4y = 1
and x- 2y +1 =0
⇒x = 2y -1
putting this value in first equation,
3(2y -1) -4y =1
⇒6y -3 -4y =1
⇒2y = 4
⇒y =2
so, x= 2×2 -1 = 3
and x- 2y +1 =0
⇒x = 2y -1
putting this value in first equation,
3(2y -1) -4y =1
⇒6y -3 -4y =1
⇒2y = 4
⇒y =2
so, x= 2×2 -1 = 3
RUTVI1:
sorry wrong answer the answer is (3,2) check it
see again...x is 3 and y is 2 ...that means (3,2) :)
yes
so now say...am i wrong?
I think so
omg...but where Rutvi??
I didn't understood your reply
you can also cross check that answer, i mean , put x =3 and y =2
Answered by
1
x = 2y -1
putting this value in first equation,
therefore 3(2y -1) -4y =1
= 6y -3 -4y =1
= 2y = 4
= y =2
so, x= 2×2 -1 = 4-1
= 3 is the answer
putting this value in first equation,
therefore 3(2y -1) -4y =1
= 6y -3 -4y =1
= 2y = 4
= y =2
so, x= 2×2 -1 = 4-1
= 3 is the answer
ok
ok
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