solve the following pair of equation by reducing them to a pair of linear equation 5/x-1+1/y-2=2,6/x-1-3/y-2=1
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(x-1)+5(y-2)=(x-1)(y-2). from eq1
(y-2)6-3(x-1)=(x-1)(y-2). from eq2
equate both
(x-1)+5(y-2)=(y-2)6-3(x-1)
4(x-1)=(y-2)
4x-4=y-2
4x-2=y
substitute y in above eq and find x value
by getting x u can find y value too.
(y-2)6-3(x-1)=(x-1)(y-2). from eq2
equate both
(x-1)+5(y-2)=(y-2)6-3(x-1)
4(x-1)=(y-2)
4x-4=y-2
4x-2=y
substitute y in above eq and find x value
by getting x u can find y value too.
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