Question

Solve the following pair of equation by substituting method:
7x-15y=2
x+2y=3​

Answer 1

Step-by-step explanation:

$\bf\huge{Solution:-}$

Given that,

$\bf{7x-15y=2}$ ----------(1)

$\bf{x+2y=3}$ ----------(2)

Step 1: We pick either of the equation and write one variable in terms of the other.

Let us consider the Equation (2):

$\bf{x+2y=3}$

and write as $\bf{ x=3-2y}$ --------(3)

Step 2: Substituting the value of x in Equation (1). We get

$\bf{:=> 7(3-2y)-15y=2}$

i.e., $\bf{:=> 21-14y-5y=2}$

i.e., $\bf{:=> -29y=-19}$

Therefore, $\bf{y=19/29}$

Step 3: Substituting this value of y in Equation (3), we get

$\bf{x=3-2(19/29)=49/29}$

Therefore, the solution is $\bf{x=49/29, y=19/29}$.

Verification: Substituting $\bf{x=49/29}$ and $\bf{y=19/29}$, we can verify that both the Equation (1) and (2) are satisfied.

Answer 2

Answer:

$\huge{\underline{\color{teal}{\textsf{\textbf{~~~Soultion}}}}}$

${ \bf{ \pmb {Given}}}$ :- Solve the following pair of equation by substituting method:

• 7x-15y=2

• x+2y=3

first find the value of x or y from anyone equation let's take x+2y=3

x + 2y = 3

x = 3 - 2y

now let's substitute the value in equation (1)

$→ \: 7x - 15y = 2 \\ →7(3 - 2y) - 15y = 2 \\ →21 - 14y - 15y = 2 \\ →29y = - 19 \\ → y = \frac{ 19}{29}$

now substitute the value of y in equation (2)

y = $\frac{19}{29}$

x = 3 - 2y

x = 3 - 2 ( $\frac{19}{29}$ )

x = 3 - $\frac{38}{29}$

x = $\frac{87-38}{29}$

x = $\frac{49}{29}$

therefore value of x = $\frac{49}{29}$ and y = $\frac{19}{29}$