Question

solve the following pair of equation graphically :2x+3y=12 2x=3y

Answer 1

Explanation:

2

x

+

3

y

=

12

is the standard form for a linear equation. To determine the slope, solve the equation for

y

in order to convert to the slope-intercept form

y

=

m

x

+

b

, where

m

is the slope and

b

is the y-intercept.

2

x

+

3

y

=

12

Subtract

2

x

from both sides.

3

y

=

−

2

x

+

Explanation:

2

x

+

3

y

=

12

is the standard form for a linear equation. To determine the slope, solve the equation for

y

in order to convert to the slope-intercept form

y

=

m

x

+

b

, where

m

is the slope and

b

is the y-intercept.

2

x

+

3

y

=

12

Subtract

2

x

from both sides.

3

y

=

−

2

x

+

12

Divide both sides by

3

.

y

=

−

2

3

x

+

12

3

=

y

=

−

2

3

Answer 2

Answer:

the point will be $(3,2)$ in graph.

Step-by-step explanation:

The Given Equations:

  $2x+3y=12$ ..........(i)

  $2x=3y$ ....................(ii)

The Values of the variables:

    $3y + 3y=12$    [$2x=3y$]

Or, $6y=12$

Or, $y= \frac{12}{6}$

 ∴ $y = 2$

    $2x=3*2$    [$y=2$]

Or, $2x=6$

Or, $x=\frac{6}{2}$

 ∴ $x=3$

So, the point will be $(3,2)$ in graph.

It is  perpendicular to the $3^{rd}$ point of the X-axis and $2^{nd}$ point of the Y-axis.

Hope you understand the process...

By- Md. Mominur Islam Mahim.