Solve the following pair of equation graphically: 4x-y=4 and 3x+2y=14
(Class 10 Maths Sample Question Paper)
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Answered by
351
Given :
4 x - y = 4…………( eq. 1)
3 x + 2 y= 14………..( eq. 2)
From eq 1
y = 4 x - 4
Put x= 0
y = 4 × 0 - 4
y = 0 - 4
y = -4
Put x= 1
y = 4 x 1 - 4
y= 4 - 4
y= 0
Put x = 2
y = 4 x - 4
y = 4 × 2 - 4
y = 8 - 4
y = 4
Table 1
X | 0 | 1 | 2 |
Y | -4 | 0 | 4 |
From eq 2
y =( 14 - 3x )/ 2
Put x= 0
y = (14-3×0)/2= (14 - 0)/2= 14/2 = 7
y = 7
Put x=2
y = (14-3×2)/2= (14 - 6)/2= 8/2 = 4
y = 4
Put x= 4
y = (14-3×4)/2= (14 - 12)/2= 2/2 = 1
y = 1
Table 2
X | 0 | 2 | 4 |
Y | 7 | 4 | 1 |
Make graph from table 1 & 2
[GRAPH IS IN THE ATTACHMENT]
As (2,4) is common , therefore solution is (2,4).
HOPE THIS WILL HELP YOU...
4 x - y = 4…………( eq. 1)
3 x + 2 y= 14………..( eq. 2)
From eq 1
y = 4 x - 4
Put x= 0
y = 4 × 0 - 4
y = 0 - 4
y = -4
Put x= 1
y = 4 x 1 - 4
y= 4 - 4
y= 0
Put x = 2
y = 4 x - 4
y = 4 × 2 - 4
y = 8 - 4
y = 4
Table 1
X | 0 | 1 | 2 |
Y | -4 | 0 | 4 |
From eq 2
y =( 14 - 3x )/ 2
Put x= 0
y = (14-3×0)/2= (14 - 0)/2= 14/2 = 7
y = 7
Put x=2
y = (14-3×2)/2= (14 - 6)/2= 8/2 = 4
y = 4
Put x= 4
y = (14-3×4)/2= (14 - 12)/2= 2/2 = 1
y = 1
Table 2
X | 0 | 2 | 4 |
Y | 7 | 4 | 1 |
Make graph from table 1 & 2
[GRAPH IS IN THE ATTACHMENT]
As (2,4) is common , therefore solution is (2,4).
HOPE THIS WILL HELP YOU...
Attachments:
Answered by
103
From graph point of intersection is (2,4).
So the solution is x=2 and y=4
The graph is attached here....Hope this will enough and helpful to u...Plz if u got the answer crct then mark it as brainliest... Plz
So the solution is x=2 and y=4
The graph is attached here....Hope this will enough and helpful to u...Plz if u got the answer crct then mark it as brainliest... Plz
Attachments:
nammu6:
how are you
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