Question

Solve the following pair of equation with elimination 5(x-2)+3y=1, 3(x+1)+5(y-3)=1

Answer 1

Answer:

x = 1 and y = 2

Step-by-step explanation:

5(x-2) + 3y =1

5x - 10 + 3y = 1

5x + 3y - 11 = 0 ....................eq. 1

3(x+1) + 5(y-3) = 1

3x + 5y - 13 = 0 ...............eq. 2

By Elimination Method,

5x + 3y - 11 = 0

3x + 5y - 13 = 0

Multiplying equation 1 by 3 and equation 2 by 5, We get

15x + 9y - 33 = 0

15x + 25y - 65 = 0

Now changing sign for lower equation, we get

9y - 25y = -16y

-33 + 65 = 32

Now,

-16y + 32 = 0

-16y = -32

y = 2

Now putting value of y in eq.1

5x + 3y - 11 = 0

5x + 3(2) -11 = 0

5x + 6 = 11

5x = 5

x = 1