Solve the following pair of equations:(1/x) + (3/y) =1(6/x)- 12/y=2
X= 5/3 , Y= 15/2
x=4,y=9
x=3,y=1
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Answer:
(i)
2x1+3y1=2
3x1+2y1=613
Lets assume x1=p and y1=q, both equations will become
2p+3q=2
⇒3p+2q=12 ... (A)
3p+2q=613
⇒2p+3q=13 ...(B)
Multiply (A) by 3 and (B) by 2, we get
9p+6q=36
4p+6q=26
Subtracting these both, we get
5p=10
⇒p=2
⇒x=p1=21
∴q=626−8=3
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