Question

solve the following pair of equations.
6/x+y=7/x-y+3. & 1/2(x+y) =1/3(x-y)​

Answer 1

Answer:

x+y=7xy.........(1)

2x−3y=−xy.........(2)

Multiply the equation 1 by 2.Then we get:

2x+2y=14xy.........(3)

Subtract equation 2 from equation 3 to eliminate x, because the coefficients of x are same. So, we get

(2x−2x)+(2y+3y)=14xy+xy

i.e. 5y=15xy

i.e. 5=15x

i.e. x=

3

1

Substituting this value of x in the equation 1, we get

3

1

+y=

3

7

y

⇒

3

1

=

3

7

y−y

⇒

3

1

=

3

4

y

⇒4y=1

⇒y=

4

1

Hence, the solution of the equations is x=

3

1

,y=

4

1

.