Solve the following pair of equations by cross multiplication method. 2x+3y=8 and 4x+5y=7
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Step-by-step explanation:
Given 2x+3y+8 = 0 ...(1) 4x+5y+14 = 0 ...(2)multiply equation. (1) by 5 and equation (2) by 3 we get10x + 15y + 40 = 0 12x + 15y + 42 = 0 - - -___________________-2x-2=0[x = -1] from equation.(1) 3y = 8 -2xy= 310 Hence using cross multiplication method intersection point of line 1 & 2 are(−1, 310 )
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