Solve the following pair of equations by substitution method 7x-15y=2 and x+2y=3.
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x+2y=3
x=-2y+3
7x-15y=2
put x=3-2y
7(3-2y)-15y=2
21-14y-15y=2
19=19y
y=1
x=3-2y
x=3-2
x=1
x=-2y+3
7x-15y=2
put x=3-2y
7(3-2y)-15y=2
21-14y-15y=2
19=19y
y=1
x=3-2y
x=3-2
x=1
birendrak1975:
sorry the answer is wrong
y=19/29
x=49/29
Sorry for the wrong answer I could not edit the mistake
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