Question

Solve the following pair of equations by substitution method: 2p + 3q = - 5 and p + 2q = - 4 .​

Answer 1

Answer:

2p+3q=-5 (1)

p+2q=-4 (2)

In (2) equation,multiply by 2 ,we get

2p+4q=-8 (3)

now by substituting,also sign change we get, q=-3 and p=2

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Answer 2

Given - 2p + 3q = - 5 and p + 2q = - 4

Find - Value of p and q

Solution - On solving the given pair of equations, the value of p and q is 2 and - 3 respectively.

Let the equation 2p + 3q = - 5 be equation 1 and the equation p + 2q = - 4 be equation 2.

Now, the value of p from equation 2 will be -

p = - 2q - 4.

Keep the derived value of p from equation 2 in equation 1.

Hence, the new equation will be -

2(- 2q - 4) + 3q = - 5

Solving the above-mentioned equation to find the value of q.

- 4q - 8 + 3q = - 5

3q - 4q = 8 - 5

-q = 3

So, q = -3.

Now, keep the value of q in equation 2 to find the value of p.

p + 2q = - 4

p + 2(-3) = - 4

p - 6 = - 4

p = 6 - 4

p = 2.

Thus, on solving the given pair of equations, the value of p and q is 2 and - 3 respectively.