solve the following pair of equations by substitution method
4x+3y=3
3x-2y=19
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Answers
Answered by
1
4x+3y=3
4x=3-3y
x=(3-3y)/4
3(3-3y)/4 -2y = 19
9-9y-8y=19*4
9-17y=76
17y=9-76
17y=-67
y=-67/17
u can find x.
4x=3-3y
x=(3-3y)/4
3(3-3y)/4 -2y = 19
9-9y-8y=19*4
9-17y=76
17y=9-76
17y=-67
y=-67/17
u can find x.
your answer is wrong
now check
Answered by
2
4x+3y=3...(I)
3x-2y=19...(ii)
y=-67/17
x=252/68
sorry for the wrong answer
ok
just for silly mistake
i don't know how to solve this problem but i have answer
hence i know how to solve the question
then please tell me how to solve
see my soluti it is step by step
wait
x=-3 and y=5
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