solve the following pair of linear equation
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1st equation => 2/√x + 3/√y = 2
2√y + 3√ x = 2√xy.
2nd equation => 4/√x - 9/√y = -1
4√y -9√x = -√xy
multiplying 1st equation by 2 .
=> 4√y+6√x = 4√xy
Now subtracting both equations.
4√y + 6√x =4√xy
4√y-9√x= -√xy
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15√x = 5√xy
3√x = √xy
√y= 3
y = 3²=9 .
Now substitute in any equation we get
2*3+ 3√x= 2*3√x.
6+ 3√x = 6√x
3√x = 6
√x = 2
x = 2² = 4 .
Therefore, (x, y) = (4,9)
√y = 9/4
2√y + 3√ x = 2√xy.
2nd equation => 4/√x - 9/√y = -1
4√y -9√x = -√xy
multiplying 1st equation by 2 .
=> 4√y+6√x = 4√xy
Now subtracting both equations.
4√y + 6√x =4√xy
4√y-9√x= -√xy
===============
15√x = 5√xy
3√x = √xy
√y= 3
y = 3²=9 .
Now substitute in any equation we get
2*3+ 3√x= 2*3√x.
6+ 3√x = 6√x
3√x = 6
√x = 2
x = 2² = 4 .
Therefore, (x, y) = (4,9)
√y = 9/4
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Answer:
2√y+3√x=2 and 4√y-9√x=-1
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