Math, asked by alishaagra99, 1 year ago

solve the following pair of linear equation

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Answered by HappiestWriter012
3
1st equation => 2/√x + 3/√y = 2

2√y + 3√ x = 2√xy.

2nd equation => 4/√x - 9/√y = -1

4√y -9√x = -√xy

multiplying 1st equation by 2 .
=> 4√y+6√x = 4√xy

Now subtracting both equations.

4√y + 6√x =4√xy
4√y-9√x= -√xy
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15√x = 5√xy

3√x = √xy

√y= 3

y = 3²=9 .

Now substitute in any equation we get

2*3+ 3√x= 2*3√x.

6+ 3√x = 6√x

3√x = 6

√x = 2

x = 2² = 4 .

Therefore, (x, y) = (4,9)

√y = 9/4
Answered by bhaktram248
0

Answer:

2√y+3√x=2 and 4√y-9√x=-1

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