solve the following pair of linear equation 21x+47=110 ,47x+21=162
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21χ= 110-47
21χ =63
χ= 63/21
χ= 3
47χ= 162-21
47χ= 141
χ= 141/47
χ=3
21χ =63
χ= 63/21
χ= 3
47χ= 162-21
47χ= 141
χ= 141/47
χ=3
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