Question

solve the following pair of linear equation 21x+47y=110,47x+21y=162

Answer 1

Hey...

The answer is in the attachment...


Hope this would help you.

__________________________________________

#Saadya

Answer 2

Answer:

(3,1)

Step-by-step explanation:

Given : $21x+47y=110$

            $47x+21y=162$

To Find: Solution.

Solution:

$21x+47y=110$   --1

$47x+21y=162$    ---2

Substitute the value of x from 1 in 2

$47\frac{110-47y}{21}+21y=162$

$47(110-47y)+441y=3402$

$5170-2209y+441y=3402$

$5170−1768y=3402$

$5170-3402=1768y$

$1768=1768y$

$y=1$

Substitute the value of y in 2 to get value of x

$47x+21(1)=162$  

$47x+21=162$  

$47x=162-21$  

$47x=141$  

$x=\frac{141}{47}$  

$x=3$  

Hence the solution is (3,1)