Solve the following pair of linear equation
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make equations bro
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(x÷2)+(2y÷3)=−13x+4y=−6(eq1)(x−y)÷3=3x−y=9(eq2)
Through substitution,
In eq2,
x=y+9. (eq3)
Putting eq3 in eq1,
3(y+9)+4y=-6
3y+27+4y=-6
7y+27=-6
7y=-6-27
7y=-33
y=-33/7
Putting (y=-33/7) in eq2,
x=-33/7+9
x=(-33+81)/7
x=48/7
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