Question

solve the following pair of linear equation 41x+53y=135 and 53x+41y=147

Answer 1

hope this will help you

Answer 2

41x+53y=135------------ (1)
53x+41y=147-------------(2)

by elimination method,

multiply 41 in eq.(1) and multiply 53 in eq.(2),

(41x+53y=135)×41
(53x+41y=147)×53

1681x+2173y=5535
2809x+2173y=7791
- - -
__________________(by subtracting)

-1128x = -2256. (2173y-2173y cancelled)
x = -2256/-1128(- and - is cancelled
x = 2

put the value of x in eq. (2),

53x+41y=147
53×2+41y=147
106+41y=147
41y=147-106
41y=41
y=41/41
y=1

so the value of x=2
y=1
Ans.

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