Solve the following pair of linear equation
4x-y=5 ; 2x-3y= -1 by elimination metho
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given equations,
4x - y = 5 ....... (1)
2x - 3y = -1 .......(2)
multiply equation (1) by 2 and equation (2) by 4 to make the coefficients of x equal,
4x - y = 5 ..... x 2
= 8x - 2y = 10 ....... (eq. 3)
2x - 3y = -1 ...... x 4
= 8x - 12y = -4 .......(eq. 4)
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now, subtract (eq.3) from (eq.4) to eliminate x, because they are same,
8x - 12y = -4
8x - 2y = 10
(-) (+)
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10y = 6
y = 6/10
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substituting value of y in (1)
4x - 6/10 = 5
4x/1 - 6/10 = 5
40x/10 - 6/10 = 5
(40x - 6)/10 = 5
40x - 6 = 50
40x = 56
x = 56/40
= 28/20
= 14/10
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