Question

solve the following pair of linear equation by cross multiplication method : 4x + 3y = 28: 9x-5y = 63​

Answer 1

Step-by-step explanation:

the solution of equation is ( 7, 3 )

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hope it helps u.

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Answer 2

The solution of the given system of linear equations is

x = 7, y = 0

Step-by-step explanation:

The given equations are

4x +3y = 28

9x -5y = 63

We can rewrite these equations as

4x +3y - 28 =0

9x -5y -63=0

Compare the equations with the below equations

$A_1x+b_1y+C_1=0\\\\A_2x+b_2y+C_2=0$

$A_1=4,B_1=3,C_1=-28\\\\A_2=9,B_2=-5,C_2=-63$

From Cross Multiplication method, the solution is given by

$\frac{x}{B_1C_2-B_2C_1}=\frac{y}{C_1A_2-C_2A_1}=\frac{1}{A_1B_2-A_2B_1}$

Substituting the known values, we get

$\frac{x}{3\cdot(-63)-(-5)(-28)}=\frac{y}{(-28)(9)-(-63)(4)}=\frac{1}{4(-5)-9(3)}\\\\\frac{x}{-329}=\frac{y}{0}=\frac{1}{-47}\\\\x=\frac{-329}{-47},y=\frac{0}{-47}\\\\x=7,y=0$

Therefore, the solution of the given system of linear equations is

x = 7

y = 0

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Cross multiplication method

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