Math, asked by 475krishnatiwari, 7 months ago

solve the following pair of linear equation by cross multiplication metjod
4x-3y=8
x-2y=-3​

Answers

Answered by VegetoBlue
0

Step-by-step explanation:

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Attachments:
Answered by snehavishwakaram
0

Answer:

y = -0.8

Step-by-step explanation:

4x-3y=8 -------(equation 1)

x-2y=-3 -------(equation 2)

multiplying equation 1 by 2;

(4x-3y=8) x2

8x-6y=16 ------- ( equation 3)

multiplying equation 2 by 3;

(x-2y=-3)x3

3x-6y=-9 ------ ( equation 4)

now;

subtracting equation 3 and 4:

8x-6y=16

3x-6y=-9

- + +

________

5x =25

x =5

substituting equation X = 5 in equation 1

4x-3y=8

4x5-3y=8

20-3y=8

-3y=8-20

-3y=-12

y =-12÷-3

y=4

(x, y) =(5,4)

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