solve the following pair of linear equation by cross multiplication metjod
4x-3y=8
x-2y=-3
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Step-by-step explanation:
seems like you are in class 10 . I hope u survive until your board exams. Stay at home , keep studying and keep playing too.
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Answer:
y = -0.8
Step-by-step explanation:
4x-3y=8 -------(equation 1)
x-2y=-3 -------(equation 2)
multiplying equation 1 by 2;
(4x-3y=8) x2
8x-6y=16 ------- ( equation 3)
multiplying equation 2 by 3;
(x-2y=-3)x3
3x-6y=-9 ------ ( equation 4)
now;
subtracting equation 3 and 4:
8x-6y=16
3x-6y=-9
- + +
________
5x =25
x =5
substituting equation X = 5 in equation 1
4x-3y=8
4x5-3y=8
20-3y=8
-3y=8-20
-3y=-12
y =-12÷-3
y=4
(x, y) =(5,4)
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