solve the following pair of linear equation by elimination method
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Hi,
Here is your answer in the attachment.....
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Here is your answer in the attachment.....
Hope it helps you....
plz mark as brainliest.......
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Heya !!
★ (1) X + Y = 9 ---------(1)
And,
3X - Y = 0 --------(2)
Adding equation (1) and equation (2) we get,
X + Y = 9
3X - Y = 0
-----------------
4X = 9
X = 9/4
Putting the value of X in equation (1)
X + Y = 9
9/4 + Y = 9
9 + 4Y = 36
4Y = 36-9
Y = 27/4
Hence,
X = 9/4 and Y = 27/4.
★ (2) X + Y = 25 ---------(1)
X + 2Y = 40 -----------(2)
Subtracting equation (1) and equation (2) we get,
X + Y = 25
X + 2Y = 40
-------------------
- Y = - 15
Y = 15
Putting the value of Y in equation (1)
X + Y = 25
X + 15 = 25
X = 10.
Hence,
X = 10 and Y = 15.
★ (3) X + 4Y = 27 ----------(1)
X + 2Y = 21 --------------(2)
Subtracting equation (1) and equation (2) we get,
X + 4Y = 27
X + 2Y = 21
------------------
2Y = 6
Y = 6/2 = 3
Putting the value of Y in equation (1)
X + 4Y = 27
X + 4 × 3 = 27
X = 27-12
X = 15
Hence,
X = 15 and Y = 3.
★ (1) X + Y = 9 ---------(1)
And,
3X - Y = 0 --------(2)
Adding equation (1) and equation (2) we get,
X + Y = 9
3X - Y = 0
-----------------
4X = 9
X = 9/4
Putting the value of X in equation (1)
X + Y = 9
9/4 + Y = 9
9 + 4Y = 36
4Y = 36-9
Y = 27/4
Hence,
X = 9/4 and Y = 27/4.
★ (2) X + Y = 25 ---------(1)
X + 2Y = 40 -----------(2)
Subtracting equation (1) and equation (2) we get,
X + Y = 25
X + 2Y = 40
-------------------
- Y = - 15
Y = 15
Putting the value of Y in equation (1)
X + Y = 25
X + 15 = 25
X = 10.
Hence,
X = 10 and Y = 15.
★ (3) X + 4Y = 27 ----------(1)
X + 2Y = 21 --------------(2)
Subtracting equation (1) and equation (2) we get,
X + 4Y = 27
X + 2Y = 21
------------------
2Y = 6
Y = 6/2 = 3
Putting the value of Y in equation (1)
X + 4Y = 27
X + 4 × 3 = 27
X = 27-12
X = 15
Hence,
X = 15 and Y = 3.
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