Question

solve the following pair of linear equation by subsitution method 3x-4y=20, 3x+2y=8​

Answer 1

Answer:

3x-4y= 20, 3x+ 2y =8

3x-4y= 20

3x+ 2y =8

(equation 1)

(equation 2)

change signs of equation 1

-3x+4y= -20

now minus second eq from first)

-4y = 12 =

y = 12 - 4

y = 8

(put in first eq)

3x+ 2y = 8

3x + 2(8) = 8

3x + 16 = 8

3x = 8 -16

x = 8/3 or 2.33