solve the following pair of linear equation by substition method
3x/2 - 5y/3 = -2
x/3 + y/2 = 13/6
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Ohh sry substitution korile ata page ot nhoe
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Alakeshkayshap:
substitution method koisilu
ata kotha porixa loi tension noloba , direct substitution buli nahe koribo , I m damm sure
aru ai tolor jone je korise , soli tak brainliest select kori de
xi vale kosto korise jen lage , tate akou helping hand
oh aru porixa kenekua hol kali
beleg method moi o koribo paru
tumar kua
yoo
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3x/2-5y/3=-2 =9×-10y=-12...... (1)
x/3+y/2=13/6 =2x+3y=13......... (2)
By equation no. (2)
x=13-3y/2..... (3)
substitute value of x in eq. (1)
9 (13-3y/2)-10y=-12
117-27y-20y=-24
47y=141 =y=3
Now, put value of y in eq. no. (3)
x=13-3×3/2 =x=2
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