Question

solve the following pair of linear equation by substitution method 2x-3y+15=0; 3x-5=0

Answer 1

by substitution method -:
 2(-50)-3(-25)+15=0

3x = 5 
x=5/3

Answer 2

Answer:

$x=\frac{5}{3}$ and $y=\frac{55}{9}$

Step-by-step explanation:

The given equations are:

$2x-3y+15=0$ and $3x-5=0$.

Taking the equation  $3x-5=0$,

⇒$x=\frac{5}{3}$

Substituting the value of x in the other equation, we get

$2(\frac{5}{3})-3y+15=0$

$\frac{10}{3}+15=3y$

$\frac{10+45}{3}=3y$

$y=\frac{55}{9}$