Question

solve the following pair of linear equation by the substitution method 3x-y=3and9x-3y=9​

Answer 1

Answer:

Infinitely many solutions.

Step-by-step explanation:

Given that;

• 3x - y = 3 ..... (i)
• 9x - 3y = 9 .. (ii)

On solving fpr the first equation;

3x - y = 3

⇒ 3x = y + 3

⇒ x = $\sf \dfrac{y + 3}{3}$

On Substituting the value of x -

$\sf 9x - 3y = 9 \\ \\ \implies \sf 9( \frac{y + 3}{3} ) - 3y= 9 \\ \\ \implies \sf 3(y + 3) - 3y = 9 \\ \\ \implies \sf 3y + 9 - 3y = 9 \\ \\ \implies \sf 9 = 9$

The statement is true for all the values of x. Hence, there are infinitely many solutions of the given equation.

Answer 2

Answer:

Infinitely many solutions.

Step-by-step explanation:

Given,

• $\large 3x - y = 3 .... ( i )$

• $\large 9x - 3y = 9 ... ( ii )$

On solving fpr the first equation:

$\large 3x - y = 3$

$\large = 3x = y + 3$

$\large = x = \frac{y + 3}{3}$

On substituting the value of x

$\large 9x - 3y = 9$

$\large = 9 ( \frac{y + 3}{3} ) - 3y = 9$

$\large = 3 ( y + 3 ) - 3y = 9$

$\large = 3y + 9 - 3y = 9$

$\large = 9 = 9$

The statement is true for all the values of x.

Hence, there are infinitely many solutions of the given equation.